5(2x^2+1)=(7x^2+17)

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Solution for 5(2x^2+1)=(7x^2+17) equation:


Simplifying
5(2x2 + 1) = (7x2 + 17)

Reorder the terms:
5(1 + 2x2) = (7x2 + 17)
(1 * 5 + 2x2 * 5) = (7x2 + 17)
(5 + 10x2) = (7x2 + 17)

Reorder the terms:
5 + 10x2 = (17 + 7x2)

Remove parenthesis around (17 + 7x2)
5 + 10x2 = 17 + 7x2

Solving
5 + 10x2 = 17 + 7x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x2' to each side of the equation.
5 + 10x2 + -7x2 = 17 + 7x2 + -7x2

Combine like terms: 10x2 + -7x2 = 3x2
5 + 3x2 = 17 + 7x2 + -7x2

Combine like terms: 7x2 + -7x2 = 0
5 + 3x2 = 17 + 0
5 + 3x2 = 17

Add '-5' to each side of the equation.
5 + -5 + 3x2 = 17 + -5

Combine like terms: 5 + -5 = 0
0 + 3x2 = 17 + -5
3x2 = 17 + -5

Combine like terms: 17 + -5 = 12
3x2 = 12

Divide each side by '3'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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